With the acquire-release semantics, we break the sequential consistency. In the acquire-release semantics, synchronization occurs between atomic operations on the same atomic and not between threads.
The acquire-release semantic is more lightweight and, therefore, faster than the sequential consistency because the synchronization only occurs between atomic operations. But although the intellectual challenge increases.
At first glance, you will notice that all operations are atomic. So the program is well-defined. But the second glance shows more. The atomic operations on y are attached with the flags std::memory_order_release (line 12) and std::memory_order_acquire (line 16). In contrast, the atomic operations on x are annotated with std::memory_order_relaxed. So there are no synchronization and ordering constraints for x. The key for the possible values for x and y can only be answered by y.
- y.store(11,std::memory_order_release) synchronizes-with y.load(std::memory_order_acquire)
- x.store(2000,std::memory_order_relaxed is visible before y.store(11,std::memory_order_release)
- y.load(std::memory_order_acquire) is visible before x.load(std::memory_order_relaxed)
I will elaborate a little bit more on these three statements. The key idea is that the store of y in line 10 synchronizes with the load of y in line 16. The reason is that the operations occur on the same atomic and follow the acquire-release semantic. So y uses std::memory_order_release in line 12 and std::memory_order_acquire in line 16. But the pairwise operations on y have another very interesting property. They establish a kind of barrier relative to y. So x.store(2000,std::memory_order_relaxed) can not be executed after y.store(std::memory_order_release), so x.load() can not be executed before y.load().
The reasoning was in the case of the acquire-release semantic more sophisticated than in the case of the sequential consistency. But the possible values for x and y are the same. Only the combination y == 11 and x == 0 is no possible.
Three different interleavings of the threads are possible, producing the three different combinations of x and y.
- thread1 will be executed before thread2.
- thread2 will be executed before thread1.
- thread1 executes x.store(2000), before thread2 will be exectued.
At the end the table.
At first, the program once more with CppMem.
We already know, all results except of (y=11, x=0) are possible.
Have a look at the three graphs with consistent execution. The graphs show an acquire-release semantics between the store-release of y and the load-acquire from y. It makes no difference if the reading of y (rf) takes place in the main thread or a separate thread. The graphs show the synchronizes-with relation with an sw arrow.
Execution for (y=0, x= 0)
Execution for (y= 0, x= 2000)
Execution for (y=11, x= 2000)
But we can do better. Why should x be atomic? There is no reason. That was my first but incorrect assumption. Why? You will read it in the next post.
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- Embedded Programmierung mit modernem C++ 12.12.2023 – 14.12.2023 (Präsenzschulung, Termingarantie)
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Here is a compilation of my standard seminars. These seminars are only meant to give you a first orientation.
- C++ – The Core Language
- C++ – The Standard Library
- C++ – Compact
- C++11 and C++14
- Concurrency with Modern C++
- Design Pattern and Architectural Pattern with C++
- Embedded Programming with Modern C++
- Generic Programming (Templates) with C++
- Clean Code with Modern C++
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