Raw and Cooked

C++11 has user-defined literals for characters, C strings, integers and floating point numbers. For integers and floating point numbers they are available in raw and cooked form. Thanks to C++14 we have built-in literals for binary numbers, C++ strings, complex numbers, and time units.

The four user-defined literals

After the example in the last post user-defined literals I will provide - as promised - in this post the details. To make my intention clear here are the literal types including the raw and cooked variations

How should you read the table? The data type character has the form character_suffix. An example is 's'_c. The compiler tries to invoke the literal operator operator"" _c('s'). The character is in this case of the type char. C++ supports in addition to the data type char the data types wchar_t, char16_t, and char32_t. You can use this types as base for your C string. I used in the table a char. The table shows that the compiler maps the C string "hi"_i18 to the literal operator operator"" _i18n("hi",2). 2 is the length of the c string.

The compiler can map integers or floating point numbers to integers (unsigned long long int) or floating point numbers (long double) but the compiler can also map them to C strings. The first variant is called cooked form; the second variant raw form. The compiler will use the raw form if the literal operator wants its arguments as C string. If not, it uses the cooked form. If you implement both versions, the compiler will choose the cooked form.

Admittedly, in the last lines is a lot of confusion potential. Therefore, I sum all up from the perspective of the signatures in the following table. The first column has the signature of the literal operator, the second column the type of the user-defined literal, and the last column an example for a user-defined literal that fits the signature of the literal operator.

Calculate it once more

I calculated in the post user-defined literals how many meters I have to go by car in average per week. I made my calculation based on user-defined literals of the type long double in the cooked form. To make my calculation in the raw from I have simply to adjust the literal operators.

It's only necessary to convert the arguments of the literal operator from type C string to long double. That is quite easy to do with the new function std::stold.

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26

// unit.h

#ifndef UNIT_H
#define UNIT_H

#include <distance.h>

namespace Distance{

  namespace Unit{
    MyDistance operator "" _km(const char* k){
      return MyDistance(1000* std::stold(k));
    }
    MyDistance operator "" _m(const char* m){
      return MyDistance(std::stold(m));
    }
    MyDistance operator "" _dm(const char* d){
      return MyDistance(std::stold(d)/10);
    }
    MyDistance operator "" _cm(const char* c){
      return MyDistance(std::stold(c)/100);
    }
  }
}

#endif

Either I have not to touch the class MyDistance.

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48

// distance.h

#ifndef DISTANCE_H
#define DISTANCE_H

#include <iostream>
#include <ostream>


namespace Distance{
  class MyDistance{
    public:
      MyDistance(double i):m(i){}

      friend MyDistance operator+(const MyDistance& a, const MyDistance& b){
        return MyDistance(a.m + b.m);
      }
      friend MyDistance operator-(const MyDistance& a,const MyDistance& b){
        return MyDistance(a.m - b.m);
      }
	  
	  friend MyDistance operator*(double m, const MyDistance& a){
	    return MyDistance(m*a.m);
	  }
	  
	  friend MyDistance operator/(const MyDistance& a, int n){
	    return MyDistance(a.m/n);
	  }
	  
      friend std::ostream& operator<< (std::ostream &out, const MyDistance& myDist){
        out << myDist.m << " m";
        return out;
      }
	private:
	  double m;
	  
  };
  
}
  
Distance::MyDistance getAverageDistance(std::initializer_list<Distance::MyDistance> inList){
  auto sum= Distance::MyDistance{0.0};
  for (auto i: inList) sum = sum + i ;
  return sum/inList.size(); 
}


#endif

Nor does the main program need a modification.

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46

// average.cpp

#include <distance.h>
#include <unit.h>

using namespace Distance::Unit;

int main(){

  std:: cout << std::endl;

  std::cout << "1.0_km: " << 1.0_km << std::endl;
  std::cout << "1.0_m: " << 1.0_m << std::endl;
  std::cout << "1.0_dm: " << 1.0_dm << std::endl;
  std::cout << "1.0_cm: " << 1.0_cm << std::endl;
  
  std::cout << std::endl;

  std::cout << "0.001 * 1.0_km: " << 0.001 * 1.0_km << std::endl;
  std::cout << "10 * 1_dm: " << 10 * 1.0_dm << std::endl;
  std::cout << "100 * 1.0cm: " << 100 * 1.0_cm << std::endl;
  std::cout << "1_.0km / 1000: " << 1.0_km / 1000 << std::endl;

  std::cout << std::endl;
  std::cout << "1.0_km + 2.0_dm +  3.0_dm + 4.0_cm: " << 1.0_km + 2.0_dm +  3.0_dm + 4.0_cm << std::endl;
  std::cout << std::endl;
  
  auto work= 63.0_km;
  auto workPerDay= 2 * work;
  auto abbrevationToWork= 5400.0_m;
  auto workout= 2 * 1600.0_m;
  auto shopping= 2 * 1200.0_m;
  
  auto distPerWeek1= 4*workPerDay-3*abbrevationToWork+ workout+ shopping;
  auto distPerWeek2= 4*workPerDay-3*abbrevationToWork+ 2*workout;
  auto distPerWeek3= 4*workout + 2*shopping;
  auto distPerWeek4= 5*workout + shopping;

  std::cout << "distPerWeek1: " << distPerWeek1 << std::endl;
  
  auto averageDistance= getAverageDistance({distPerWeek1,distPerWeek2,distPerWeek3,distPerWeek4});
  std::cout<< "averageDistance: " << averageDistance << std::endl;
  
  std::cout << std::endl;

}

Of course, the result is the same.

New built-in literals with C++14

C++ added with C++14 a few new built-in literals. These are built-in literals for binary numbers, C++ strings, complex numbers, time unites. At first as ever the overview.

You have to keep a few special rules in mind. The binary numbers start with the prefix 0b. The built-in literals have no underscore. That is different from the user-defined literals. C++ support with C++14 the first time a C++ string literal. So far C++ supports only C string literals. That means for example that you always have to use a C string literal to initialize a C++ string. That was very strange. The time literals are very convenient because they implicitly know their unit. They are of the type std::chrono::duration.

The base unit for time is the second. My 16 years old son often complains that its school day is so exhausting. Of course ehe question arises. How many seconds does my son need for a typical school day? The program gives the answer.

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30

// literals.cpp

#include <iostream>
#include <chrono>

using namespace std::literals::chrono_literals;

int main(){

  std::cout << std::endl;

  auto schoolHour= 45min;

  auto shortBreak= 300s;
  auto longBreak= 0.25h;

  auto schoolWay= 15min;
  auto homework= 2h;

  auto schoolDayInSeconds= 2*schoolWay + 6 * schoolHour + 4 * shortBreak + longBreak + homework;
  
  std::cout << "School day in seconds: " << schoolDayInSeconds.count() << std::endl;
  
  std::cout << "School day in minutes: " << schoolDayInSeconds.count() / 60 << std::endl;
  
  std::cout << "School day in hours: " << schoolDayInSeconds.count() / 3600 << std::endl;

  std::cout << std::endl;

I think the program is totally self-explanatory. The suffixes are expressive enough. Making the correct additions is the job of the compiler. The time literals support the base arithmetic addition, subtraction, multiplication, division, and modulo operation.

I have no C++14 compliant compiler at my disposal. Not really an issue. The online compiler on en.cppreference.com gives me the answers

My son needs 27300 seconds for all his task related to school. This is almost a typical working day in Germany of about 8 hours.

What's next?

The classical enumerations (enum) in C++ have three big disadvantages.

1. They convert implicitly to int.
2. They introduce their enumerators into the enclosing scope.
3. The type of the enumerators can not be defined.

In particular, characteristics 1 and 2 are often a reason for bad surprises. The new strong-typed enumerations clear off with these issues. Read about it in the next post.