The autogenerated Equality Operator

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You can define the three-way comparison operator or request it from the compiler with =default. But do you know that you can also define or request the equality operator in C++20?

Before I dive into the autogenerated equality operator, I’d like to refresh your knowledge about the three-way comparison operator.

The Three-Way Comparison Operator

You can define the three-way comparison operator or request it from the compiler with =default. You get all six comparison operators in both cases: ==, !=, <, <=, >, and >=.

// threeWayComparison.cpp

#include <compare>
#include <iostream>

struct MyInt {
    int value;
    explicit MyInt(int val): value{val} { }
    auto operator<=>(const MyInt& rhs) const {           // (1)      
        return value <=> rhs.value;
    }
};

struct MyDouble {
    double value;
    explicit constexpr MyDouble(double val): value{val} { }
    auto operator<=>(const MyDouble&) const = default;   // (2)
};

template <typename T>
constexpr bool isLessThan(const T& lhs, const T& rhs) {
    return lhs < rhs;
}

int main() {
    
    std::cout << std::boolalpha << std::endl;
    
    MyInt myInt1(2011);
    MyInt myInt2(2014);
    
    std::cout << "isLessThan(myInt1, myInt2): "
              << isLessThan(myInt1, myInt2) << std::endl;
              
    MyDouble myDouble1(2011);
    MyDouble myDouble2(2014);
    
    std::cout << "isLessThan(myDouble1, myDouble2): "
              << isLessThan(myDouble1, myDouble2) << std::endl;          
              
    std::cout << std::endl;
              
}

The user-defined (1) and the compiler-generated (2) three-way comparison operators work as expected.

But there are a few subtle differences in this case. The compiler-deduced return type for MyInt (1) supports strong ordering, and the compiler-deduced return type of MyDouble supports partial ordering. Floating pointer numbers only support partial ordering because floating-point values such as NaN (Not a Number) can not be ordered. For example, NaN == NaN  is false.

The compiler-generated three-way comparison operator needs the header <compare>, which is implicit constexpr and noexcept. Additionally, it performs a lexicographical comparison. Lexicographical comparison means that all base classes are compared left to right and all non-static members in their declaration order.

Let’s assume I add a std::unordered_set to both classes MyInt and MyDouble. 

struct MyInt {
    int value;
    std::unordered_set<int> mySet;
    explicit MyInt(int val): value{val}, mySet{val} { }
    bool operator<=>(const MyInt& rhs) const {
        if (auto first = value <=> rhs.value; first != 0) return first;
        else return mySet <=> rhs.mySet; 
    }
};

struct MyDouble {
    double value;
    std::unordered_set<double> mySet;
    explicit MyDouble(double val): value{val}, mySet{val} { }
    bool operator<=>(const MyDouble&) const = default;   
};

Requesting or defining the three-way comparison fails because std::unordered_set does not support ordering. std::unordered_set only support equality comparison, and so does MyInt and MyDouble.

Equality Operator

When you define or request the equality operator from the compiler with =default, you automatically
get the equality and inequality operators: ==, and !=.

// equalityOperator.cpp

#include <iostream>
#include <tuple>
#include <unordered_set>

struct MyInt {
    int value;
    std::unordered_set<int> mySet;
    explicit MyInt(int val): value{val}, mySet{val} { }
    bool operator==(const MyInt& rhs) const {                 
        return std::tie(value, mySet) == std::tie(rhs.value, rhs.mySet);
    }
};

struct MyDouble {
    double value;
    std::unordered_set<double> mySet;
    explicit MyDouble(double val): value{val}, mySet{val} { }
    bool operator==(const MyDouble&) const = default;   
};

template <typename T>
constexpr bool areEqual(const T& lhs, const T& rhs) {

    return lhs == rhs;
}

template <typename T>
constexpr bool areNotEqual(const T& lhs, const T& rhs) {

    return lhs != rhs;
}

int main() {
    
    std::cout << std::boolalpha << '\n';
    
    MyInt myInt1(2011);
    MyInt myInt2(2014);
    
    std::cout << "areEqual(myInt1, myInt2): "
              << areEqual(myInt1, myInt2) << '\n';
    std::cout << "areNotEqual(myInt1, myInt2): "
              << areNotEqual(myInt1, myInt2) << '\n';

    std::cout << '\n';          
              
    MyDouble myDouble1(2011.0);
    MyDouble myDouble2(2014.0);
    
    std::cout << "areEqual(myDouble1, myDouble2): "
              << areEqual(myDouble1, myDouble2) << '\n';
    std::cout << "areNotEqual(myDouble1, myDouble2): "
              << areNotEqual(myDouble1, myDouble2) << '\n';           
              
    std::cout << '\n';
              
}

Now, I can compare MyInt and MyDouble for equality and inequality.

 

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    I applied a neat trick in the program equalityOperator.cpp. Can you spot it?

    In the following example, I implemented the equality operator of MyInt by chaining the equality operators of value and mySet.

    struct MyInt {
    int value;
    std::unordered_set<int> mySet;
    explicit MyInt(int val): value{val}, mySet{val} { }
    bool operator==(const MyInt& rhs) const {
        if (auto first = value == rhs.value; first != 0) return first;
        else return mySet == rhs.mySet; 
    }
};

    This is pretty ugly and error-prone if you have a class with more members

    On the contrary, I used std::tie to implement the equality operator in the program equalityOperator.cpp.

    struct MyInt {
    int value;
    std::unordered_set<int> mySet;
    explicit MyInt(int val): value{val}, mySet{val} { }
    bool operator==(const MyInt& rhs) const {                 
        return std::tie(value, mySet) == std::tie(rhs.value, rhs.mySet);
    }
};

    std::tie creates a tuple of lvalue references to its arguments. Finally, the created tuples are lexicographically compared.

    What’s Next?

    In my next post, I will continue my journey through C++20 and write about std::span. std::span represents an object that refers to a contiguous sequence of objects.

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