templates

From Variadic Templates to Fold Expressions

In my last two posts, “Variadic Templates or the Power of Three Dots” and “More about Variadic Templates“, I introduced variadic templates. This post goes one step further in the future, and presents fold expressions that can directly reduce a parameter pack with a binary operator. 

templates

I intentionally skipped one import use case for variadic templates: the perfect factory function. When you combine perfect forwarding with variadic templates, you get the perfect factory function. The perfect factory function is a function that can accept an arbitrary number of arguments of any value category (lvalue or rvalue). Curious? Read my previous post, “C++ Core Guidelines: Rules for Variadic Templates“.

But now, I want to present something new with fold expressions.

Fold Expressions

C++11 supports variadic templates. These are templates that can accept an arbitrary number of template parameters. A so-called parameter pack holds the arbitrary number. Additionally, with C++17, we got fold expressions. Thanks to fold expressions, you can directly reduce a parameter pack with a binary operator. Let’s look at reducing an arbitrary number of numbers to a value.

 

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    // variadicTemplatesFoldExpression.cpp
    
    #include <iostream>
    
    bool allVar() {                                              // (1)
        return true;
    }
    
    template<typename T, typename ...Ts>                         // (2)
    bool allVar(T t, Ts ... ts) {                                // (3)
        return t && allVar(ts...);                               // (4)
    }
    
    template<typename... Args>                                   // (5)
    bool all(Args... args) { return (... && args); }            
    
    int main() {
    
        std::cout << std::boolalpha;
    
        std::cout << '\n';
    
        std::cout << "allVar(): " << allVar() << '\n';
        std::cout << "all(): " << all() << '\n';
    
        std::cout << "allVar(true): " << allVar(true) << '\n';
        std::cout << "all(true): " << all(true) << '\n';
    
        std::cout << "allVar(true, true, true, false): " 
                  << allVar(true, true, true, false) << '\n';
        std::cout << "all(true, true, true, false): " 
                  << all(true, true, true, false) << '\n';
    
        std::cout << '\n';
    
    }
    

     

    Both function templates allVar and all return at compile time if all arguments are true. allVar uses variadic templates; all fold expressions.

    The variadic templates allVar applies recursion to evaluate its arguments. The function allVar (1) is the boundary condition if the parameter pack is empty. The recursion takes place in the function template allVar (2). The three dots stand for the so-called parameter pack. Parameter packs support two operations. You can pack or unpack them. It is packed in line (2); unpacked in (3) and (4).

    Line (4) requires our full attention. Here, the head of the parameter pack t is combined with the rest ts of the parameter pack ts using the binary operator &&. The call allVar(ts …) triggers the recursion. The call includes a parameter pack that is the original one reduced by the head. Fold expressions (5) make our job easier. With fold expressions, you can directly reduce the parameter pack with the help of the binary operator: (... && args).

    Here is the output of the program.

    variadicTemplatesFoldExpressios

     A fold expression applies a binary operator to a parameter pack.

    Application of the binary Operator

    A fold expression can apply the binary operator in two different ways.

    1. With and without an initial value.
    2. Fold the variadic pack from left or from right

    There is a subtle difference between the algorithm allVar and all. All have the default value true for the empty parameter pack.

    C++17 supports 32 binary operators in fold expressions: “+ – * / % ^ & | = < > << >> += -= *= /= %= ^= &= |= <<= >>= == != <= >= && || , .* ->*” . A few of them have default-values:

     BinaryOperatorDefault

    You have to provide an initial value for binary operators with no default value. You can specify an initial value for binary operators with a default value.

    If the ellipsis stands left of the parameter pack, the parameter pack will be processed from the left. If right of the parameter pack, it will be processed from the right. This is also true if you provide an initial value.

    Fold expression allows it to implement Haskell functions foldl, foldr, foldl1, and foldr1 direct in C++.

     A Flavor of Haskell

    The following table shows the four variations of fold expression and their Haskell pendants. The C++17 standard requires that fold expressions with initial value use the same binary operator op.

    foldExpressions

    The C++  and Haskell variations differ in two points. The C++ version uses the default value as the initial value; the Haskell version uses the first element as the initial value. The C++ version processes the parameter pack at compile time, and the Haskell version processes its list at run time. 

    The following program shows all four variations of fold expression. Each one subtracts a few numbers.

     

    // foldVariations.cpp
    
    #include <iostream>
    
    template<typename... Args>                   // (1)
    auto diffL1(Args const&... args) {
        return (... - args);
    }
    
    template<typename... Args>                   // (2)
    auto diffR1(Args const&... args) {
        return (args - ...);
    }
    
    template<typename Init, typename... Args>    // (3)
    auto diffL(Init init, Args const&... args) {
        return (init - ... - args);
    }
    
    template<typename Init, typename... Args>    // (4)
    auto diffR(Init init, Args const&... args) {
        return (args - ... - init);
    }
    
    int main() {
    
        std::cout << '\n';
    
        std::cout << "diffL1(1, 2, 3): " << diffL1(1, 2, 3) << '\n';       // (1 - 2) - 3
        std::cout << "diffR1(1, 2, 3): " << diffR1(1, 2, 3) << '\n';       // 1 - (2 - 3)
        std::cout << "diffL(10, 1, 2, 3): " << diffL(10, 1, 2, 3) << '\n'; // ((10 - 1) - 2) - 3
        std::cout << "diffR(10, 1, 2, 3): " << diffR(10, 1, 2, 3) << '\n'; // 1 - (2 - (3 - 10))
    
        std::cout << '\n';
    
    }
    

     

    The functions diffL1 (1) and diffL (3) process the numbers from the left and the functions diffR1 (2) and diffR (3) process them from the right. Additionally, the functions diffL and diffR use an initial start value. The comments in the main function shows the processing steps.

    foldVariations

     I execute the Haskell pendant directly in the Haskell shell.

    foldHaskell

    What’s next?

    Variadic templates, particularly fold expressions, enable it to write concise expressions for repeated operations. Learn more about it in my next post.

     

     

     

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