This post is about template interfaces which are due to the C++ core guidelines: "...a critical concept", because a template interface is "a contract between a user and an implementer - and should be carefully designed.".

Here are the rules for today:
Let me start with the first rule T.41:
What does it mean to specify only the essential properties? The guidelines provide an example of a sort algorithm that has debug support.
template<Sortable S>
requires Streamable<S>
void sort(S& s) // sort sequence s
{
if (debug) cerr << "enter sort( " << s << ")\n";
// ...
if (debug) cerr << "exit sort( " << s << ")\n";
}
Now, one question remains: What is the issue if you specify non-essential properties. This means that your concepts are strongly bound to the implementation. The result may be that a small change of the implementation changes your concepts. In the end, your interface becomes quite unstable.
Since C++11 we have templates aliases. A template alias is a name that refers to a family of types. Using them makes your code more readable and helps you to get rid of type traits. My previous post C++ Core Guidelines: Definition of Concepts, the Second provides more information to type traits.
Let's see what the guidelines mean by readability. The first example uses type traits:
template<typename T>
void user(T& c)
{
// ...
typename container_traits<T>::value_type x; // bad, verbose
// ...
}
Here is the corresponding case with template aliases.
template<typename T>
using Value_type = typename container_traits<T>::value_type;
void user2(T& c)
{
// ...
Value_type<T> x;
// ...
}
Readability is also the argument that holds for the next rule
There are two arguments from the readability perspective to prefer using over typedef. First, using comes first when used. Second, using feels quite similar to auto. Additionally, using can easily be used for template aliases.
typedef int (*PFI)(int); // OK, but convoluted
using PFI2 = int (*)(int); // OK, preferred
template<typename T>
typedef int (*PFT)(T); // error (1)
template<typename T>
using PFT2 = int (*)(T); // OK
The first two lines define a pointer to a function (PFI and PFI2) which takes an int and returns an int. In the first case typedef is used and in the second line using. The last two lines define a function template (PFT2) which takes a type parameter T and returns an int. Line (1) is not valid.
The primary reason that we have too many make_ functions such as std::make_tuple or std::make_unique is that a function template can deduce its template arguments from its function arguments. During this process, the compiler applies a few simple conversions such as removing the outermost const/volatile qualifier and decaying C-arrays and functions to a pointer to the first element of the C-array or a pointer to the function.
This automatic template argument deduction makes our life as a programmer much easier.
Instead of typing
std::tuple<int, double, std::string> myTuple = {2011, 20.11, "C++11"};
you use the factory function std::make_tuple.
auto myTuple = std::make_tuple(2011, 20.11, "C++11");
Sad to say but automatic template type deduction is in C++ only available for function templates. Why? Constructors of class templates are a special static function. Right! With C++17, the compiler can deduce its template arguments from its constructor arguments. Here is the way to define myTuple in C++17.
std::tuple myTuple = {2017, 20.17, "C++17"};
An obvious effect of this C++17 feature is that most of the make_ function become obsolete with C++17.
If you want to know the details about class template argument deduction including the argument deduction guide, read the post Modern C++ Features - Class Template Argument Deduction from Arne Mertz.
Teachability of C++
I have to admit, I like this C++17 feature. As a C++ trainer, my job is it to explain this difficult stuff. The more symmetric C++ becomes the easier is it for me to speak about the general ideas. Now I can say: "A template can automatically deduce its template arguments from its function arguments.". In the past, I had to say this works only for function templates.
Here is a simple example:
// templateArgumentDeduction.cpp
#include <iostream>
template <typename T>
void showMe(const T& t){
std::cout << t << std::endl;
}
template <typename T>
struct ShowMe{
ShowMe(const T& t){
std::cout << t << std::endl;
}
};
int main(){
std::cout << std::endl;
showMe(5.5); // not showMe<double>(5.5);
showMe(5); // not showMe<int>(5);
ShowMe(5.5); // not ShowMe<double>(5.5);
ShowMe(5); // not ShowMe<int>(5);
std::cout << std::endl;
}
The usage of the function template showMe or the class template ShowMe feels the same. From the user perspective, you don't know that you use a template.
With a current GCC 8.2, the program compiles and runs.

To be more specific template argument deduction should work since GCC 7, Clang 5, and MSVC 19.14. cppreference.com gives you the details of the compiler support.
What's next?
Do you know what a Regular or SemiRegular type is? If not, the next post to template interfaces is just the right one for you. Rule T.46 states: "Require template arguments to be at least Regular or SemiRegular.".
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